文章主要介绍了php返回相对时间的方法,可实现返回如：20分钟前、3天前等格式时间,非常具有实用价值,需要的朋友可以参考下。
本文实例讲述了php返回相对时间（如：20分钟前，3天前）的'方法。分享给大家供大家参考。具体如下：
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function plural($num) {
if ($num != 1)
return "s";
}
function getRelativeTime($date) {
$diff = time() - strtotime($date);
if ($diff<60)
return $diff." 秒"al($diff)." 前";
$diff = round($diff/60);
if ($diff<60)
return $diff." 分钟"al($diff)." 前";
$diff = round($diff/60);
if ($diff<24)
return $diff." 小时"al($diff)." 前";
$diff = round($diff/24);
if ($diff<7)
return $diff." 天"al($diff)." 前";
$diff = round($diff/7);
if ($diff<4)
return $diff." 星期"al($diff)." 前";
return "on "("F j, Y", strtotime($date));
}
希望本文所述对大家的php程序设计有所帮助。
【拓展阅读】
这里以一种可读性比较好的方式显示已经过去多长时间，比如：距离现在10秒，距离现在1天等等。
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function time_is_older_than($t, $check_time){
$t = strtolower($t);
$time_type = substr(preg_replace('/[^a-z]/', '', $t), 0, 1);
$val = intval(preg_replace('/[^0-9]/', '', $t));
$ts = 0;
// (s)econds, (m)inutes, (d)ays, (y)ears
if ($time_type == 's'){ $ts = $val; }
else if ($time_type == 'm'){ $ts = $val * 60; }
else if ($time_type == 'h'){ $ts = $val * 60 * 60; }
else if ($time_type == 'd'){ $ts = $val * 60 * 60 * 24; }
else if ($time_type == 'y'){ $ts = $val * 60 * 60 * 24 * 365; }
else { die('Unknown time format given!'); }
if ($check_time < (time()-$ts)){ return true; }
return false;
}
//使用范例：
// timestamp to test:
// (could be from an database or something else)
$time = 1146722922;
// long if check:
if (time_is_older_than('30m', $time)){
print 'The given timestamp: ' . date('l dS of F Y h:i:s A',$time);
print " - is older than 30 minutes<br/>n";
}
else {
print 'The given timestamp: ' . date('l dS of F Y h:i:s A',$time);
print " - is NOT older than 30 minutes<br/>n";
}
// short checks:
if (time_is_older_than('10s', $time)){ print "Is older than 10 seconds<br/>n"; }
if (time_is_older_than('200m', $time)){ print "Is older than 200 minutes<br/>n"; }
if (time_is_older_than('2h', $time)){ print "Is older than 2 hours<br/>n"; }
if (time_is_older_than('4d', $time)){ print "Is older than 4 days<br/>n"; }
if (time_is_older_than('1y', $time)){ print "Is older than one year<br/>n"; }
